from functools import reducedef str2float(s): m=len(s) - s.find('.') - 1 s = s.replace('.', '') DIGITS = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9} def char2num(s): return DIGITS[s] s1=reduce(lambda x, y: x * 10 + y, map(char2num, s)) return s1/(10**m)
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绿绿的小蚂蚱