L1 = ['Hello', 'World', 18, 'Apple', None]
L2 = [i.lower() for i in L1 if isinstance(i, str)]
print(L2)
这样L2中会丢掉L1中的[18,None]这两个元素吧？
期待输出: ['hello', 'world', 'apple'] 这样应该不用考虑18和None两个元素 List Comprehension应该不好实现都输出的情况
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小菘Barry
-- coding: utf-8 --
L1 = ['Hello', 'World', 18, 'Apple', None]
L2 = [i.lower() for i in L1 if isinstance(i, str)]
print(L2)