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zuoye

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别摸我大腿

#1 Created at ... [Delete] [Delete and Lock User] 
n = (b*b - 4*a*c)
if n > 0:
    x1 = (-b + math.sqrt(n)) / (2*a)
    x2 = (-b - math.sqrt(n)) / (2*a)
    return x1, x2

elif n == 0:
    x1 == x2 == -b/(2*a)
    return x1

else:
    print('无解')
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