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复习了一元二次方程组，现在好想回去把5年高考3年模拟翻开做做，呵呵

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可可豆公子

#1 Created at ... [Delete] [Delete and Lock User]

-- coding: utf-8 --

import math def quadratic(a,b,c): x1 = (-b + math.sqrt(b2 - 4ac))/2*a; x2 = (-b - math.sqrt(b2 - 4ac))/2*a; return x1,x2

print(quadratic(2, 3, 1)) # => (-0.5, -1.0) print(quadratic(1, 3, -4)) # => (1.0, -4.0)

可可豆公子

#2 Created at ... [Delete] [Delete and Lock User] 
# -*- coding: utf-8 -*-
import math
def quadratic(a,b,c):
    x1 = (-b + math.sqrt(b**2 - 4*a*c))/2*a;
    x2 = (-b - math.sqrt(b**2 - 4*a*c))/2*a;
    return x1,x2

print(quadratic(2, 3, 1)) # => (-0.5, -1.0)
print(quadratic(1, 3, -4)) # => (1.0, -4.0)

可可豆公子

#3 Created at ... [Delete] [Delete and Lock User]

我突然发现，我多打了两个分号居然也运行了

可可豆公子

#4 Created at ... [Delete] [Delete and Lock User] 
# -*- coding: utf-8 -*-
import math
def quadratic(a,b,c):
    if not (isinstance(a, int) and isinstance(b, int) and isinstance(c, int)):
        raise TypeError('bad operand type')
    x1 = (-b + math.sqrt(b**2 - 4*a*c))/2*a
    x2 = (-b - math.sqrt(b**2 - 4*a*c))/2*a
    return x1,x2

print(quadratic(1, "b", 1)) # => (-0.5, -1.0)
print(quadratic(1, 3, -4)) # => (1.0, -4.0)

孑儒犬

#5 Created at ... [Delete] [Delete and Lock User]

＃一个简单的，乘以2的函数，为什么算不出来呀，求教哪里错了。

import math def q(a,b): x=2a y=2b return x,y print(q(3,5)) SyntaxError: invalid syntax

CanYouImagineMeWithoutYou

#6 Created at ... [Delete] [Delete and Lock User]

不能用2a,要写成2*a

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