package Threads.Test11;public class ThreadLocalTests { public static void main(String[] args) { //测试ThreadLocal使用方法 ThreadLocal<String> studentName = new ThreadLocal<>(); new Thread(()->{ studentName.set("xiaoming"); System.out.println(Thread.currentThread().getName()+":学生姓名是-"+studentName.get()); studentName.remove(); System.out.println(Thread.currentThread().getName()+":学生姓名是-"+studentName.get()); }).start(); new Thread(()->{ studentName.set("xiaozhang"); System.out.println(Thread.currentThread().getName()+":学生姓名是-"+studentName.get()); }).start(); } } 结果: Thread-0:学生姓名是-xiaoming Thread-0:学生姓名是-null Thread-1:学生姓名是-xiaozhang Process finished with exit code 0
例子只给了存储个String 按照php的说法就是个字符串, 那我想存储一个数组或者 对象 咋整。
帮忙回复下二楼的兄弟。
将楼主的这一行 String
ThreadLocal<String> studentName = new ThreadLocal
替换为某个对象 例如User
ThreadLocal<User> studentName = new ThreadLocal
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